Repeat Purchases on Multiple Days – SQL Question Asked by Stitch Fix

  • Post last modified:December 15, 2022
  • Reading time:2 mins read
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  • In this article we will solve Repeat Purchases on Multiple Days SQL question which is asked by Stitch Fix as per DataLemur website.

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  • We have been given purchases table which contains purchases made by different user on different days.
  • We have to output number of users who made purchase of same product on two or more days.


  • We will first partition our purchase table by user_id and product id, this partition will be order by date in ascending order. we will assign rank within each partition.
  • In the output we can see that most of the user_id and product_id combination has rank of 1.
  • We should be interested in the rank 2 because that would help us to get the user who purchased same product on two different days.
  • for user 333, we can see rank is 1 for all the records because purchase date is same for all of them.
  • but let’s consider user_id 536, this user bought same product at two different days hence the rank is different.
  • Now all we have to do is to just filter out cases where rank is greater than equal to 2 and count such users.

Final Solution

  • Here is our final solution.
select count(distinct user_id) from(
select user_id, product_id , 
rank() over(partition by user_id,product_id order by date(purchase_date) asc) as rnk 
from purchases
 ) x
 where rnk >=2


  • Our solution is accepted by the platform.


  • In this article we solved SQL question asked by Stitch Fix. In This question we used sql windowing operation ranking to get the output.

Bonus Tip

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